detailed information: The input equation set is: Question solving process:
Multiply both sides of equation (1) by 4 Divide the two sides of equation (1) by 3, the equation can be obtained: , then add the two sides of equation (6) to both sides of equation (2), the equations are reduced to:
| | | | | 9 | B | | - | 4 3 | C | | -3 | D | | - | 4 3 | E | = | | 24 | | (2) |
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Divide the two sides of equation (1) by 3, the equation can be obtained: , then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
| | | | | 9 | B | | - | 4 3 | C | | -3 | D | | - | 4 3 | E | = | | 24 | | (2) |
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Divide the two sides of equation (1) by 3, the equation can be obtained: , then add the two sides of equation (8) to both sides of equation (5), the equations are reduced to:
| | | | | 9 | B | | - | 4 3 | C | | -3 | D | | - | 4 3 | E | = | | 24 | | (2) |
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Divide the two sides of equation (2) by 9, the equation can be obtained: | | B | | - | 4 27 | C | | - | 1 3 | D | | - | 4 27 | E | = | | | 8 3 | (9) | , then add the two sides of equation (9) to both sides of equation (4), the equations are reduced to:
| | | | | 9 | B | | - | 4 3 | C | | -3 | D | | - | 4 3 | E | = | | 24 | | (2) |
| | - | 4 27 | C | + | | | 8 3 | D | | - | 4 27 | E | = | | | 44 3 | | (4) |
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Multiply both sides of equation (3) by 4 Divide the two sides of equation (3) by 45, the equation can be obtained: | | | 4 27 | C | | - | 16 135 | E | = | | - | 16 15 | (10) | , then add the two sides of equation (10) to both sides of equation (4), the equations are reduced to:
| | | | | 9 | B | | - | 4 3 | C | | -3 | D | | - | 4 3 | E | = | | 24 | | (2) |
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Multiply both sides of equation (3) by 4 Divide the two sides of equation (3) by 5, the equation can be obtained: , then add the two sides of equation (11) to both sides of equation (5), the equations are reduced to:
| | | | | 9 | B | | - | 4 3 | C | | -3 | D | | - | 4 3 | E | = | | 24 | | (2) |
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Multiply both sides of equation (5) by 2 Divide both sides of equation (5) by 27, get the equation:, then add the two sides of equation (12) to both sides of equation (4), get the equation:
| | | | | 9 | B | | - | 4 3 | C | | -3 | D | | - | 4 3 | E | = | | 24 | | (2) |
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Multiply both sides of equation (5) by 10 Divide both sides of equation (5) by 27, get the equation:, then add the two sides of equation (13) to both sides of equation (3), get the equation:
| | | | | 9 | B | | - | 4 3 | C | | -3 | D | | - | 4 3 | E | = | | 24 | | (2) |
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Multiply both sides of equation (5) by 10 Divide both sides of equation (5) by 27, get the equation:, then add the two sides of equation (14) to both sides of equation (2), get the equation:
Multiply both sides of equation (5) by 5 Divide both sides of equation (5) by 18, get the equation:, then add the two sides of equation (15) to both sides of equation (1), get the equation:
Multiply both sides of equation (4) by 9 Divide both sides of equation (4) by 8, get the equation:, then add the two sides of equation (16) to both sides of equation (2), get the equation:
Multiply both sides of equation (3) by 4 Divide both sides of equation (3) by 5, get the equation:, then add the two sides of equation (17) to both sides of equation (2), get the equation:
Multiply both sides of equation (3) by 3 Divide both sides of equation (3) by 5, get the equation:, then add the two sides of equation (18) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |