Mathematics
         
语言：中文    Language:English
Equations   
Fold
Unary equation
Multivariate equation
Math OP  
Unfold
Linear algebra      
Unfold
Derivative function
Function image
Hot issues
On line solution of multivariate equations：
    First set the elements of the equation (i.e. the number of unknowns), then click the "Next" button to enter the coefficients of each element of the equation set, and click the "Next" button to obtain the solution of the equation set.
    Note that the coefficients of each element of the equation system can only be numbers, not algebraic expressions (including mathematical functions).
    Current location：Equations > Multivariate equations > Answer
detailed information：
The input equation set is:
 A + B -1C = 0    (1)
 C + D + E = 0    (2)
 3A -2B = -15    (3)
 2B + 2C -3D = -5    (4)
 3D -1E = -3    (5)
Question solving process:

Multiply both sides of equation (1) by 3, the equation can be obtained:
         3A + 3B -3C = 0    (6)
, then subtract both sides of equation (6) from both sides of equation (3), the equations are reduced to:
 A + B -1C = 0    (1)
 C + D + E = 0    (2)
-5B + 3C = -15    (3)
 2B + 2C -3D = -5    (4)
 3D -1E = -3    (5)

交After the exchange of equation (2) and equation (3)， the equation system becomes:
 A + B -1C = 0    (1)
-5B + 3C = -15    (2)
 C + D + E = 0    (3)
 2B + 2C -3D = -5    (4)
 3D -1E = -3    (5)

Multiply both sides of equation (2) by 2
Divide the two sides of equation (2) by 5, the equation can be obtained:
        -2B + 
6
5
C = -6    (7)
, then add the two sides of equation (7) to both sides of equation (4), the equations are reduced to:
 A + B -1C = 0    (1)
-5B + 3C = -15    (2)
 C + D + E = 0    (3)
 
16
5
C -3D = -11    (4)
 3D -1E = -3    (5)

Multiply both sides of equation (3) by 16
Divide the two sides of equation (3) by 5, the equation can be obtained:
         
16
5
C + 
16
5
D + 
16
5
E = 0    (8)
, then subtract both sides of equation (8) from both sides of equation (4), the equations are reduced to:
 A + B -1C = 0    (1)
-5B + 3C = -15    (2)
 C + D + E = 0    (3)
- 
31
5
D - 
16
5
E = -11    (4)
 3D -1E = -3    (5)

Multiply both sides of equation (4) by 15
Divide the two sides of equation (4) by 31, the equation can be obtained:
        -3D - 
48
31
E = - 
165
31
    (9)
, then add the two sides of equation (9) to both sides of equation (5), the equations are reduced to:
 A + B -1C = 0    (1)
-5B + 3C = -15    (2)
 C + D + E = 0    (3)
- 
31
5
D - 
16
5
E = -11    (4)
- 
79
31
E = - 
258
31
    (5)

Multiply both sides of equation (5) by 496
Divide both sides of equation (5) by 395, get the equation：
        - 
16
5
E = - 
4128
395
    (10)
, then subtract both sides of equation (10) from both sides of equation (4), get the equation：
 A + B -1C = 0    (1)
-5B + 3C = -15    (2)
 C + D + E = 0    (3)
- 
31
5
D = - 
217
395
    (4)
- 
79
31
E = - 
258
31
    (5)

Multiply both sides of equation (5) by 31
Divide both sides of equation (5) by 79, get the equation：
        -1E = - 
258
79
    (11)
, then add the two sides of equation (11) to both sides of equation (3), get the equation：
 A + B -1C = 0    (1)
-5B + 3C = -15    (2)
 C + D = - 
258
79
    (3)
- 
31
5
D = - 
217
395
    (4)
- 
79
31
E = - 
258
31
    (5)

Multiply both sides of equation (4) by 5
Divide both sides of equation (4) by 31, get the equation：
        -1D = - 
7
79
    (12)
, then add the two sides of equation (12) to both sides of equation (3), get the equation：
 A + B -1C = 0    (1)
-5B + 3C = -15    (2)
 C = - 
265
79
    (3)
- 
31
5
D = - 
217
395
    (4)
 E = 
258
79
    (5)

Multiply both sides of equation (3) by 3, get the equation：
         3C = - 
795
79
    (13)
, then subtract both sides of equation (13) from both sides of equation (2), get the equation：
 A + B -1C = 0    (1)
-5B = - 
390
79
    (2)
 C = - 
265
79
    (3)
 D = 
7
79
    (4)
 E = 
258
79
    (5)

Add both sides of equation (3) to both sides of equation (1), get the equation：
 A + B = - 
265
79
    (1)
-5B = - 
390
79
    (2)
 C = - 
265
79
    (3)
 D = 
7
79
    (4)
 E = 
258
79
    (5)

Divide both sides of equation (2) by 5, get the equation：
        -1B = - 
78
79
    (14)
, then add the two sides of equation (14) to both sides of equation (1), get the equation：
 A = - 
343
79
    (1)
-5B = - 
390
79
    (2)
 C = - 
265
79
    (3)
 D = 
7
79
    (4)
 E = 
258
79
    (5)

The coefficient of the unknown number is reduced to 1, and the equations are reduced to：
 A = - 
343
79
    (1)
 B = 
78
79
    (2)
 C = - 
265
79
    (3)
 D = 
7
79
    (4)
 E = 
258
79
    (5)


Therefore, the solution of the equation set is:
A = - 
343
79
B = 
78
79
C = - 
265
79
D = 
7
79
E = 
258
79


Convert the solution of the equation set to decimals:
A = -4.341772
B = 0.987342
C = -3.354430
D = 0.088608
E = 3.265823

解方程组的详细方法请参阅：《多元一次方程组的解法》
return







  New addition:Lenders ToolBox module（Specific location：Math OP > Lenders ToolBox ），welcome。