detailed information: The input equation set is:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| | 2 | A | | -1 | B | + | | 3 | C | | -4 | D | + | | 2 | E | = | | 8 | | (2) |
| | 3 | A | + | | B | | -1 | C | | -2 | D | | -1 | E | = | | 3 | | (3) |
| | 4 | A | + | | 3 | B | + | | 4 | C | | -2 | D | + | | 2 | E | = | | 2 | | (4) |
| | A | | -1 | B | | -1 | C | | -2 | D | | -3 | E | = | | -3 | | (5) |
| Question solving process:
Multiply both sides of equation (1) by 2, the equation can be obtained: | | 2 | A | + | | 4 | B | | -4 | C | | -8 | D | | -2 | E | = | | -2 | (6) | , then subtract both sides of equation (6) from both sides of equation (2), the equations are reduced to:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
| | 3 | A | + | | B | | -1 | C | | -2 | D | | -1 | E | = | | 3 | | (3) |
| | 4 | A | + | | 3 | B | + | | 4 | C | | -2 | D | + | | 2 | E | = | | 2 | | (4) |
| | A | | -1 | B | | -1 | C | | -2 | D | | -3 | E | = | | -3 | | (5) |
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Multiply both sides of equation (1) by 3, the equation can be obtained: | | 3 | A | + | | 6 | B | | -6 | C | | -12 | D | | -3 | E | = | | -3 | (7) | , then subtract both sides of equation (7) from both sides of equation (3), the equations are reduced to:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
| -5 | B | + | | 5 | C | + | | 10 | D | + | | 2 | E | = | | 6 | | (3) |
| | 4 | A | + | | 3 | B | + | | 4 | C | | -2 | D | + | | 2 | E | = | | 2 | | (4) |
| | A | | -1 | B | | -1 | C | | -2 | D | | -3 | E | = | | -3 | | (5) |
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Multiply both sides of equation (1) by 4, the equation can be obtained: | | 4 | A | + | | 8 | B | | -8 | C | | -16 | D | | -4 | E | = | | -4 | (8) | , then subtract both sides of equation (8) from both sides of equation (4), the equations are reduced to:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
| -5 | B | + | | 5 | C | + | | 10 | D | + | | 2 | E | = | | 6 | | (3) |
| -5 | B | + | | 12 | C | + | | 14 | D | + | | 6 | E | = | | 6 | | (4) |
| | A | | -1 | B | | -1 | C | | -2 | D | | -3 | E | = | | -3 | | (5) |
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Subtract both sides of equation (1) from both sides of equation (5) ,the equations are reduced to:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
| -5 | B | + | | 5 | C | + | | 10 | D | + | | 2 | E | = | | 6 | | (3) |
| -5 | B | + | | 12 | C | + | | 14 | D | + | | 6 | E | = | | 6 | | (4) |
| -3 | B | + | | C | + | | 2 | D | | -2 | E | = | | -2 | | (5) |
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Subtract both sides of equation (2) from both sides of equation (3) ,the equations are reduced to:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
| | -5 | B | + | | 12 | C | + | | 14 | D | + | | 6 | E | = | | 6 | | (4) |
| -3 | B | + | | C | + | | 2 | D | | -2 | E | = | | -2 | | (5) |
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Subtract both sides of equation (2) from both sides of equation (4) ,the equations are reduced to:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
| | | -3 | B | + | | C | + | | 2 | D | | -2 | E | = | | -2 | | (5) |
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Multiply both sides of equation (2) by 3 Divide the two sides of equation (2) by 5, the equation can be obtained: | -3 | B | + | | | 21 5 | C | + | | | 12 5 | D | + | | | 12 5 | E | = | | 6 | (9) | , then subtract both sides of equation (9) from both sides of equation (5), the equations are reduced to:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
| | | - | 16 5 | C | | - | 2 5 | D | | - | 22 5 | E | = | | -8 | | (5) |
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Multiply both sides of equation (3) by 5 Divide the two sides of equation (3) by 2, the equation can be obtained: , then add the two sides of equation (10) to both sides of equation (4), the equations are reduced to:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
| | | - | 16 5 | C | | - | 2 5 | D | | - | 22 5 | E | = | | -8 | | (5) |
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Multiply both sides of equation (3) by 8 Divide the two sides of equation (3) by 5, the equation can be obtained: | - | 16 5 | C | + | | | 48 5 | D | | - | 16 5 | E | = | | - | 32 5 | (11) | , then subtract both sides of equation (11) from both sides of equation (5), the equations are reduced to:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
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Multiply both sides of equation (4) by 2 Divide the two sides of equation (4) by 5, the equation can be obtained: , then add the two sides of equation (12) to both sides of equation (5), the equations are reduced to:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
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Multiply both sides of equation (5) by 5 Divide both sides of equation (5) by 4, get the equation:, then subtract both sides of equation (13) from both sides of equation (4), get the equation:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
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Multiply both sides of equation (5) by 5 Divide both sides of equation (5) by 6, get the equation:, then subtract both sides of equation (14) from both sides of equation (3), get the equation:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
| -5 | B | + | | 7 | C | + | | 4 | D | + | | 4 | E | = | | 10 | | (2) |
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Multiply both sides of equation (5) by 5 Divide both sides of equation (5) by 3, get the equation:, then add the two sides of equation (15) to both sides of equation (2), get the equation:
 | | | | A | + | | 2 | B | | -2 | C | | -4 | D | | -1 | E | = | | -1 | | (1) |
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Multiply both sides of equation (5) by 5 Divide both sides of equation (5) by 12, get the equation:, then subtract both sides of equation (16) from both sides of equation (1), get the equation:
Multiply both sides of equation (4) by 6 Divide both sides of equation (4) by 25, get the equation:, then subtract both sides of equation (17) from both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 4 Divide both sides of equation (4) by 25, get the equation:, then subtract both sides of equation (18) from both sides of equation (2), get the equation:
Multiply both sides of equation (4) by 4 Divide both sides of equation (4) by 25, get the equation:, then add the two sides of equation (19) to both sides of equation (1), get the equation:
Multiply both sides of equation (3) by 7 Divide both sides of equation (3) by 2, get the equation:, then add the two sides of equation (20) to both sides of equation (2), get the equation:
Subtract both sides of equation (3) from both sides of equation (1), get the equation:
Multiply both sides of equation (2) by 2 Divide both sides of equation (2) by 5, get the equation:, then add the two sides of equation (21) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |