detailed information: The input equation set is:
 | | | | | | -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (3) |
| | -2 | A | + | | | 88 125 | C | + | | 2 | D | + | | E | = | | 1 | | (4) |
| | Question solving process:
Multiply both sides of equation (1) by 100 Divide the two sides of equation (1) by 33, the equation can be obtained: , then subtract both sides of equation (6) from both sides of equation (4), the equations are reduced to:
 | | | | | | -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (3) |
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交After the exchange of equation (2) and equation (3), the equation system becomes:
 | | | | | -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
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Divide the two sides of equation (2) by 3, the equation can be obtained: | | -1 | B | + | | | 71 125 | C | + | | | 2 3 | E | = | | 2 | (7) | , then add the two sides of equation (7) to both sides of equation (5), the equations are reduced to:
 | | | | | -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
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Multiply both sides of equation (3) by 88 Divide the two sides of equation (3) by 125, the equation can be obtained: | | | | 88 125 | C | + | | | 88 125 | D | = | | | 176 125 | (8) | , then subtract both sides of equation (8) from both sides of equation (4), the equations are reduced to:
 | | | | | -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
| | | | | 162 125 | D | + | | E | = | | - | 51 125 | | (4) |
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Multiply both sides of equation (3) by 17 Divide the two sides of equation (3) by 125, the equation can be obtained: | | | | 17 125 | C | + | | | 17 125 | D | = | | | 34 125 | (9) | , then add the two sides of equation (9) to both sides of equation (5), the equations are reduced to:
 | | | | | -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
| | | | | 162 125 | D | + | | E | = | | - | 51 125 | | (4) |
| | | | 17 125 | D | + | | | 2 3 | E | = | | | 284 125 | | (5) |
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Multiply both sides of equation (4) by 17 Divide the two sides of equation (4) by 162, the equation can be obtained: | | | | 17 125 | D | + | | | 17 162 | E | = | | - | 289 6750 | (10) | , then subtract both sides of equation (10) from both sides of equation (5), the equations are reduced to:
 | | | | | -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
| | | | | 162 125 | D | + | | E | = | | - | 51 125 | | (4) |
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Multiply both sides of equation (5) by 162 Divide both sides of equation (5) by 91, get the equation:, then subtract both sides of equation (11) from both sides of equation (4), get the equation:
 | | | | | -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
| | | | | 162 125 | D | = | | - | 51516 11375 | | (4) |
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Multiply both sides of equation (5) by 324 Divide both sides of equation (5) by 91, get the equation:, then subtract both sides of equation (12) from both sides of equation (2), get the equation:
 | | | | | -3 | B | + | | | 213 125 | C | = | | - | 204 91 | | (2) |
| | | | | 162 125 | D | = | | - | 51516 11375 | | (4) |
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Multiply both sides of equation (4) by 125 Divide both sides of equation (4) by 162, get the equation:, then subtract both sides of equation (13) from both sides of equation (3), get the equation:
 | | | | | -3 | B | + | | | 213 125 | C | = | | - | 204 91 | | (2) |
| | | | | 162 125 | D | = | | - | 51516 11375 | | (4) |
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Multiply both sides of equation (3) by 213 Divide both sides of equation (3) by 125, get the equation:, then subtract both sides of equation (14) from both sides of equation (2), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |