detailed information: The input equation set is:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | + | | F | + | | G | = | | 50 | | (1) |
| | | | | | | Question solving process:
Subtract both sides of equation (1) from both sides of equation (2) ,the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | + | | F | + | | G | = | | 50 | | (1) |
| | | | | | |
Add both sides of equation (2) to both sides of equation (3) ,the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | + | | F | + | | G | = | | 50 | | (1) |
| | | | | | |
Add both sides of equation (3) to both sides of equation (4) ,the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | + | | F | + | | G | = | | 50 | | (1) |
| | | | | | |
Multiply both sides of equation (4) by 4, the equation can be obtained: | | | 4 | D | + | | 4 | E | + | | 4 | F | + | | 8 | G | = | | 144 | (8) | , then subtract both sides of equation (8) from both sides of equation (5), the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | + | | F | + | | G | = | | 50 | | (1) |
| | | | | | |
Multiply both sides of equation (5) by 2 Divide both sides of equation (5) by 9, get the equation:, then add the two sides of equation (9) to both sides of equation (4), get the equation:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | + | | F | + | | G | = | | 50 | | (1) |
| | | | | | |
Divide both sides of equation (5) by 9, get the equation:, then add the two sides of equation (10) to both sides of equation (3), get the equation:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | + | | F | + | | G | = | | 50 | | (1) |
| | | | | | |
Divide both sides of equation (5) by 9, get the equation:, then add the two sides of equation (11) to both sides of equation (1), get the equation:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | + | | F | = | | 34 | | (1) |
| | | | | | |
Subtract both sides of equation (4) from both sides of equation (3), get the equation:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | + | | F | = | | 34 | | (1) |
| | | | | | |
Subtract both sides of equation (4) from both sides of equation (1), get the equation:
Subtract both sides of equation (3) from both sides of equation (2), get the equation:
Add both sides of equation (3) to both sides of equation (1), get the equation:
Add both sides of equation (2) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Where: E, F are arbitrary constants. 解方程组的详细方法请参阅:《多元一次方程组的解法》 |