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On line solution of multivariate equations:
    First set the elements of the equation (i.e. the number of unknowns), then click the "Next" button to enter the coefficients of each element of the equation set, and click the "Next" button to obtain the solution of the equation set.
    Note that the coefficients of each element of the equation system can only be numbers, not algebraic expressions (including mathematical functions).
    Current location:Equations > Multivariate equations > Answer
detailed information:
The input equation set is:
 
43
2
A 
5
2
B -15C = 0    (1)
 19A + 10B = 14    (2)
 A + C 
7
5
D = 0    (3)
-1A -1D = 0    (4)
Question solving process:

Multiply both sides of equation (1) by 38
Divide the two sides of equation (1) by 43, the equation can be obtained:
         19A 
95
43
B 
570
43
C = 0    (5)
, then subtract both sides of equation (5) from both sides of equation (2), the equations are reduced to:
 
43
2
A 
5
2
B -15C = 0    (1)
 
525
43
B + 
570
43
C = 14    (2)
 A + C 
7
5
D = 0    (3)
-1A -1D = 0    (4)

Multiply both sides of equation (1) by 2
Divide the two sides of equation (1) by 43, the equation can be obtained:
         A 
5
43
B 
30
43
C = 0    (6)
, then subtract both sides of equation (6) from both sides of equation (3), the equations are reduced to:
 
43
2
A 
5
2
B -15C = 0    (1)
 
525
43
B + 
570
43
C = 14    (2)
 
5
43
B + 
73
43
C 
301
215
D = 0    (3)
-1A -1D = 0    (4)

Multiply both sides of equation (1) by 2
Divide the two sides of equation (1) by 43, the equation can be obtained:
         A 
5
43
B 
30
43
C = 0    (7)
, then add the two sides of equation (7) to both sides of equation (4), the equations are reduced to:
 
43
2
A 
5
2
B -15C = 0    (1)
 
525
43
B + 
570
43
C = 14    (2)
 
5
43
B + 
73
43
C 
301
215
D = 0    (3)
5
43
B 
30
43
C -1D = 0    (4)

Divide the two sides of equation (2) by 105, the equation can be obtained:
         
5
43
B + 
38
301
C = 
2
15
    (8)
, then subtract both sides of equation (8) from both sides of equation (3), the equations are reduced to:
 
43
2
A 
5
2
B -15C = 0    (1)
 
525
43
B + 
570
43
C = 14    (2)
 
473
301
C 
301
215
D = 
2
15
    (3)
5
43
B 
30
43
C -1D = 0    (4)

Divide the two sides of equation (2) by 105, the equation can be obtained:
         
5
43
B + 
38
301
C = 
2
15
    (9)
, then add the two sides of equation (9) to both sides of equation (4), the equations are reduced to:
 
43
2
A 
5
2
B -15C = 0    (1)
 
525
43
B + 
570
43
C = 14    (2)
 
473
301
C 
301
215
D = 
2
15
    (3)
172
301
C -1D = 
2
15
    (4)

Multiply both sides of equation (3) by 172
Divide the two sides of equation (3) by 473, the equation can be obtained:
         
172
301
C 
1204
2365
D = 
344
7095
    (10)
, then add the two sides of equation (10) to both sides of equation (4), the equations are reduced to:
 
43
2
A 
5
2
B -15C = 0    (1)
 
525
43
B + 
570
43
C = 14    (2)
 
473
301
C 
301
215
D = 
2
15
    (3)
83
55
D = 
602
7095
    (4)

Multiply both sides of equation (4) by 3311
Divide both sides of equation (4) by 3569, get the equation:
        
301
215
D = 
98
1245
    (11)
, then subtract both sides of equation (11) from both sides of equation (3), get the equation:
 
43
2
A 
5
2
B -15C = 0    (1)
 
525
43
B + 
570
43
C = 14    (2)
 
473
301
C = 
88
415
    (3)
83
55
D = 
602
7095
    (4)

Multiply both sides of equation (3) by 3990
Divide both sides of equation (3) by 473, get the equation:
         
570
43
C = 
6384
3569
    (12)
, then subtract both sides of equation (12) from both sides of equation (2), get the equation:
 
43
2
A 
5
2
B -15C = 0    (1)
 
525
43
B = 
56350
3569
    (2)
 
473
301
C = 
88
415
    (3)
 D = 
602
10707
    (4)

Multiply both sides of equation (3) by 4515
Divide both sides of equation (3) by 473, get the equation:
         15C = 
168
83
    (13)
, then add the two sides of equation (13) to both sides of equation (1), get the equation:
 
43
2
A 
5
2
B = 
168
83
    (1)
 
525
43
B = 
56350
3569
    (2)
 
473
301
C = 
88
415
    (3)
 D = 
602
10707
    (4)

Multiply both sides of equation (2) by 43
Divide both sides of equation (2) by 210, get the equation:
         
5
2
B = 
805
249
    (14)
, then add the two sides of equation (14) to both sides of equation (1), get the equation:
 
43
2
A = 
301
249
    (1)
 
525
43
B = 
56350
3569
    (2)
 C = 
56
415
    (3)
 D = 
602
10707
    (4)

The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
 A = 
14
249
    (1)
 B = 
322
249
    (2)
 C = 
56
415
    (3)
 D = 
602
10707
    (4)


Therefore, the solution of the equation set is:
A = 
14
249
B = 
322
249
C = 
56
415
D = 
602
10707


Convert the solution of the equation set to decimals:
A = 0.056225
B = 1.293173
C = -0.134940
D = -0.056225

解方程组的详细方法请参阅:《多元一次方程组的解法》