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Assignment:Find the solution set of inequality (500-100/(60000-X))×0.75+(500-100/(20000-X))×0.25 ≥500-100/30000 .
Question type: Inequality
Solution:
The inequality can be reduced to 1 inequality:
( 500 - 100 / ( 60000 - X ) ) × 0.75 + ( 500 - 100 / ( 20000 - X ) ) × 0.25 ≥500 - 100 / 30000 (1)
From the definition field of divisor
60000 - x ≠ 0 (2 )
From the definition field of divisor
20000 - x ≠ 0 (3 )
From inequality(1):
X ≤ 6972.243623
From inequality(2):
X ∈ R (R为全体实数),即在实数范围内,不等式恒成立!
From inequality(3):
X ∈ R (R为全体实数),即在实数范围内,不等式恒成立!
From inequalities (1) and (2)
X ≤ 6972.243623 (4)
From inequalities (3) and (4)
X ≤ 6972.243623 (5)
The final solution set is :
X ≤ 6972.243623Your problem has not been solved here? Please take a look at the hot problems !