Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality e^（x+lnx） ≥x+lnx+1 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         e ^ ( x + ln x ) ≥ x + ln x + 1         (1)
        From the definition field of ln
        x > 0        (2 )
        From the definition field of ln
        x > 0        (3 )

---

    From inequality(1)：
         x ≤ 567143/1000000 或  567143/1000000 ≤ x ≤ 567143/1000000 或  x ≥ 567143/1000000
    From inequality(2)：
         x ＞ 0
    From inequality(3)：
         x ＞ 0

---

    From inequalities (1) and (2)
         0 < x ≤ 567143/1000000 或  567143/1000000 ≤ x ≤ 567143/1000000 或  x ≥ 567143/1000000    (4)
    From inequalities (3) and (4)
         0 < x ≤ 567143/1000000 或  567143/1000000 ≤ x ≤ 567143/1000000 或  x ≥ 567143/1000000    (5)

---

    The final solution set is :
         0 < x ≤ 567143/1000000 或  567143/1000000 ≤ x ≤ 567143/1000000 或  x ≥ 567143/1000000

Your problem has not been solved here? Please take a look at the  hot problems ！