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Assignment:Find the solution set of inequality -5 <= (-√a^2+1)+a <= -4 .
Question type: Inequality
Solution:
The inequality can be reduced to 2 inequalities:
-5 <= ( -√ a ^ 2 + 1 ) + a (1)
( -√ a ^ 2 + 1 ) + a <= -4 (2)
From the definition field of √
x ≥ 0 (3 )
From inequality(1):
a ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
From inequality(2):
The solution set is empty, that is, within the range of real numbers, the inequality will never be established!
From inequality(3):
a ≥ 0
The final solution set is :
The solution set is empty,that is, the inequality will never be estatlished within the real number range.
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