Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality 3x^2+6/(x^2+1) <6sqrt(2) .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
        3 * x ^ 2 + 6 / ( x ^ 2 + 1 ) <6 * sqrt ( 2 )         (1)
        From the definition field of divisor
         x ^ 2 + 1 ≠ 0        (2 )

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    From inequality(1)：
         -1.484674 < x < 1.484674
    From inequality(2)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！

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    From inequalities (1) and (2)
         -1.484674 < x < 1.484674     (3)

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    The final solution set is :
         -1.484674 < x < 1.484674

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