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    Work: Find the solution of equation {x-1}{x+1}2 = 0 .
    Question type: Equation
    Solution:Original question:

(

x

−

1

)

(

x

+

1

)

×

2

=

0

    Remove the bracket on the left of the equation:

Left side of the equation =

x

(

x

+

1

)

×

2

−

1

(

x

+

1

)

×

2

=

x

(

x

+

1

)

×

2

−

2

(

x

+

1

)

=

x

x

×

2

+

x

×

1

×

2

−

2

(

x

+

1

)

=

x

x

×

2

+

x

×

2

−

2

(

x

+

1

)

=

x

x

×

2

+

2

x

−

2

x

−

2

×

1

=

x

x

×

2

+

2

x

−

2

x

−

2

=

x

x

×

2

+

0

x

−

2

    The equation is transformed into :

x

x

×

2

+

0

x

−

2

=

0

    After the equation is converted into a general formula, it is converted into:
    ( x + 1 )( x - 1 )=0
    From
        x + 1 = 0
        x - 1 = 0
    it is concluded that:：
        x₁=-1
        x₂=1    
    There are 2 solution(s).

解一元二次方程的详细方法请参阅：《一元二次方程的解法》

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