There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ 3arccos(x) + arccos(3x - 4{x}^{3})\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = 3arccos(x) + arccos(3x - 4x^{3})\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 3arccos(x) + arccos(3x - 4x^{3})\right)}{dx}\\=&3(\frac{-(1)}{((1 - (x)^{2})^{\frac{1}{2}})}) + (\frac{-(3 - 4*3x^{2})}{((1 - (3x - 4x^{3})^{2})^{\frac{1}{2}})})\\=&\frac{12x^{2}}{(-9x^{2} + 24x^{4} - 16x^{6} + 1)^{\frac{1}{2}}} - \frac{3}{(-x^{2} + 1)^{\frac{1}{2}}} - \frac{3}{(-9x^{2} + 24x^{4} - 16x^{6} + 1)^{\frac{1}{2}}}\\ \end{split}\end{equation} \]

Your problem has not been solved here? Please take a look at the  hot problems ！