Mathematics
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Language:English

current location:Equations > Multivariate equations > Answer
Detailed information:
The input equation set is:
 x = 10    (1)
-2x + y -1z = 0    (2)
-11x + 3y + 10z = 2    (3)
Question solving process:

Multiply both sides of equation (1) by 2, the equation can be obtained:
         2x = 20    (4)
, then add the two sides of equation (4) to both sides of equation (2), the equations are reduced to:
 x = 10    (1)
 y -1z = 20    (2)
-11x + 3y + 10z = 2    (3)

Multiply both sides of equation (1) by 11, the equation can be obtained:
         11x = 110    (5)
, then add the two sides of equation (5) to both sides of equation (3), the equations are reduced to:
 x = 10    (1)
 y -1z = 20    (2)
 3y + 10z = 112    (3)

Multiply both sides of equation (2) by 3, the equation can be obtained:
         3y -3z = 60    (6)
, then subtract both sides of equation (6) from both sides of equation (3), the equations are reduced to:
 x = 10    (1)
 y -1z = 20    (2)
 13z = 52    (3)

Divide both sides of equation (3) by 13, get the equation:
         z = 4    (7)
, then add the two sides of equation (7) to both sides of equation (2), get the equation:
 x = 10    (1)
 y = 24    (2)
 13z = 52    (3)

The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
 x = 10    (1)
 y = 24    (2)
 z = 4    (3)


Therefore, the solution of the equation set is:
x = 10
y = 24
z = 4

解方程组的详细方法请参阅:《多元一次方程组的解法》
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