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〖1/1算式〗
作业:求算式 0.25*1396.12*(1+0.567)^2*((1-0.567)-160/1600)+0.5*1396.12*sin12.826 的值.
题型:数学计算
解:
0.25*1396.12*(1+0.567)^2*((1-0.567)-160/1600)+0.5*1396.12*sin12.826
=0.25*1396.12*1.567^2*((1-0.567)-160/1600)+0.5*1396.12*sin12.826
=0.25*1396.12*1.567^2*(0.433-160/1600)+0.5*1396.12*sin12.826
=0.25*1396.12*1.567^2*0.333+0.5*1396.12*sin12.826
=0.25*1396.12*1.567^2*0.333+0.5*1396.12*0.256722
=0.25*1396.12*2.455489*0.333+0.5*1396.12*0.256722
=349.03*2.455489*0.333+0.5*1396.12*0.256722
=857.039326*0.333+0.5*1396.12*0.256722
=285.394096+0.5*1396.12*0.256722
=285.394096+698.06*0.256722
=285.394096+179.207359
=464.601455 答案:0.25*1396.12*(1+0.567)^2*((1-0.567)-160/1600)+0.5*1396.12*sin12.826=464.601455 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!