本次共计算 1 个题目：每一题对 a 求 1 阶导数。
    注意，变量是区分大小写的。
\[ \begin{equation}\begin{split}【1/1】求函数(2d{\frac{1}{(4dr - {a}^{2})}}^{\frac{1}{2}})arctan(\frac{{(4dr - {a}^{2})}^{\frac{1}{2}}}{a}) 关于 a 的 1 阶导数：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = \frac{2darctan(\frac{(4dr - a^{2})^{\frac{1}{2}}}{a})}{(4dr - a^{2})^{\frac{1}{2}}}\\&\color{blue}{函数的第 1 阶导数：}\\&\frac{d\left( \frac{2darctan(\frac{(4dr - a^{2})^{\frac{1}{2}}}{a})}{(4dr - a^{2})^{\frac{1}{2}}}\right)}{da}\\=&2(\frac{\frac{-1}{2}(0 - 2a)}{(4dr - a^{2})^{\frac{3}{2}}})darctan(\frac{(4dr - a^{2})^{\frac{1}{2}}}{a}) + \frac{2d(\frac{(\frac{(\frac{\frac{1}{2}(0 - 2a)}{(4dr - a^{2})^{\frac{1}{2}}})}{a} + \frac{(4dr - a^{2})^{\frac{1}{2}}*-1}{a^{2}})}{(1 + (\frac{(4dr - a^{2})^{\frac{1}{2}}}{a})^{2})})}{(4dr - a^{2})^{\frac{1}{2}}}\\=&\frac{2daarctan(\frac{(4dr - a^{2})^{\frac{1}{2}}}{a})}{(4dr - a^{2})^{\frac{3}{2}}} - \frac{1}{2r} - \frac{a^{2}}{2(4dr - a^{2})r}\\ \end{split}\end{equation} \]

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