总述：本次共解1题。其中
           ☆算术计算1题

〖1/1算式〗
    作业：求算式 ((0.5*tan10+tan26.1)/(1-0.5*tan10*tan26.1)-1/tan26.1)/((0.5*tan20+tan(26.1*2))/(1-0.5*tan20*tan(26.1*2))-1/tan(26.1*2)) 的值.
    题型：数学计算
    解:
          ((0.5*tan10+tan26.1)/(1-0.5*tan10*tan26.1)-1/tan26.1)/((0.5*tan20+tan(26.1*2))/(1-0.5*tan20*tan(26.1*2))-1/tan(26.1*2))
        =(1.774837/(1-0.5*tan10*tan26.1)-1/tan26.1)/((0.5*tan20+tan(26.1*2))/(1-0.5*tan20*tan(26.1*2))-1/tan(26.1*2))
        =(1.774837/0.529726-1/tan26.1)/((0.5*tan20+tan(26.1*2))/(1-0.5*tan20*tan(26.1*2))-1/tan(26.1*2))
        =2.661138/((0.5*tan20+tan(26.1*2))/(1-0.5*tan20*tan(26.1*2))-1/tan(26.1*2))
        =2.661138/((0.5*tan20+tan52.2)/(1-0.5*tan20*tan(26.1*2))-1/tan(26.1*2))
        =2.661138/((-1.508455)/(1-0.5*tan20*tan(26.1*2))-1/tan(26.1*2))
        =2.661138/(-1.508455/(1-0.5*tan20*tan52.2)-1/tan(26.1*2))
        =2.661138/(-1.508455/3.938549-1/tan(26.1*2))
        =2.661138/(-1.508455/3.938549-1/tan52.2)
        =2.661138/(-0.002341)
        =-1136.75267
    答案:((0.5*tan10+tan26.1)/(1-0.5*tan10*tan26.1)-1/tan26.1)/((0.5*tan20+tan(26.1*2))/(1-0.5*tan20*tan(26.1*2))-1/tan(26.1*2))=-1136.75267
    注：弧度制

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