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☆算术计算1题
〖1/1算式〗
作业:求算式 -4000-1000/(1+0.1)+600*(1-(1+0.1)^29)/(1-(1+0.1))*(1+0.1)^2 的值.
题型:数学计算
解:
-4000-1000/(1+0.1)+600*(1-(1+0.1)^29)/(1-(1+0.1))*(1+0.1)^2
=-4000-1000/1.1+600*(1-(1+0.1)^29)/(1-(1+0.1))*(1+0.1)^2
=-4000-1000/1.1+600*(1-1.1^29)/(1-(1+0.1))*(1+0.1)^2
=-4000-1000/1.1+600*(-14.863093)/(1-(1+0.1))*(1+0.1)^2
=-4000-1000/1.1+600*(-14.863093)/(1-1.1)*(1+0.1)^2
=-4000-1000/1.1+600*(-14.863093)/(-0.1)*(1+0.1)^2
=-4000-1000/1.1+600*(-14.863093)/(-0.1)*1.1^2
=-4000-1000/1.1+600*(-14.863093)/(-0.1)*1.21
=-4000-909.090909+600*(-14.863093)/(-0.1)*1.21
=-4000-909.090909+(-8917.8558)/(-0.1)*1.21
=-4000-909.090909+89178.558*1.21
=-4000-909.090909+107906.05518
=-4909.090909+107906.05518
=102996.964271 答案:-4000-1000/(1+0.1)+600*(1-(1+0.1)^29)/(1-(1+0.1))*(1+0.1)^2=102996.964271你的问题在这里没有得到解决?请到 热门难题 里面看看吧!