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〖1/1算式〗
作业:求算式 sin(0.513113209)*(3*cos(0.513113209)-2)/(3*cos(0.513113209)^2-2*cos(0.513113209)+2) 的值.
题型:数学计算
解:
sin(0.513113209)*(3*cos(0.513113209)-2)/(3*cos(0.513113209)^2-2*cos(0.513113209)+2)
=sin0.513113209*(3*cos(0.513113209)-2)/(3*cos(0.513113209)^2-2*cos(0.513113209)+2)
=sin0.513113209*(3*cos0.513113209-2)/(3*cos(0.513113209)^2-2*cos(0.513113209)+2)
=sin0.513113209*0.61366/(3*cos(0.513113209)^2-2*cos(0.513113209)+2)
=sin0.513113209*0.61366/(3*cos0.513113209^2-2*cos(0.513113209)+2)
=sin0.513113209*0.61366/(3*cos0.513113209^2-2*cos0.513113209+2)
=sin0.513113209*0.61366/2.534633
=0.490892*0.61366/2.534633
=0.301241/2.534633
=0.11885 答案:sin(0.513113209)*(3*cos(0.513113209)-2)/(3*cos(0.513113209)^2-2*cos(0.513113209)+2)=0.11885 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!