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〖1/1算式〗
作业:求算式 ((110.8-110)*2+(109.4-110)*2+(111.2-110)*2+(109.5-110)*2+(109.1-110)*2)/5 的值.
题型:数学计算
解:
((110.8-110)*2+(109.4-110)*2+(111.2-110)*2+(109.5-110)*2+(109.1-110)*2)/5
=(0.8*2+(109.4-110)*2+(111.2-110)*2+(109.5-110)*2+(109.1-110)*2)/5
=(0.8*2+(-0.6)*2+(111.2-110)*2+(109.5-110)*2+(109.1-110)*2)/5
=(0.8*2+(-0.6)*2+1.2*2+(109.5-110)*2+(109.1-110)*2)/5
=(0.8*2+(-0.6)*2+1.2*2+(-0.5)*2+(109.1-110)*2)/5
=(0.8*2+(-0.6)*2+1.2*2+(-0.5)*2+(-0.9)*2)/5
=0/5
=0 答案:((110.8-110)*2+(109.4-110)*2+(111.2-110)*2+(109.5-110)*2+(109.1-110)*2)/5=0你的问题在这里没有得到解决?请到 热门难题 里面看看吧!