本次共计算 1 个题目：每一题对 e 求 1 阶导数。
    注意，变量是区分大小写的。
\[ \begin{equation}\begin{split}【1/1】求函数b(-((csqrt(e + c)m - \frac{csqrt(e - 1)}{(c{m}^{2} - 2cm + 1)})(1 + csqrt(e - s{e}^{2})))) 关于 e 的 1 阶导数：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = - bc^{2}msqrt(e - se^{2})sqrt(e + c) - bcmsqrt(e + c) + \frac{bc^{2}sqrt(e - se^{2})sqrt(e - 1)}{(cm^{2} - 2cm + 1)} + \frac{bcsqrt(e - 1)}{(cm^{2} - 2cm + 1)}\\&\color{blue}{函数的第 1 阶导数：}\\&\frac{d\left( - bc^{2}msqrt(e - se^{2})sqrt(e + c) - bcmsqrt(e + c) + \frac{bc^{2}sqrt(e - se^{2})sqrt(e - 1)}{(cm^{2} - 2cm + 1)} + \frac{bcsqrt(e - 1)}{(cm^{2} - 2cm + 1)}\right)}{de}\\=& - \frac{bc^{2}m(1 - s*2e)*\frac{1}{2}sqrt(e + c)}{(e - se^{2})^{\frac{1}{2}}} - \frac{bc^{2}msqrt(e - se^{2})(1 + 0)*\frac{1}{2}}{(e + c)^{\frac{1}{2}}} - \frac{bcm(1 + 0)*\frac{1}{2}}{(e + c)^{\frac{1}{2}}} + (\frac{-(0 + 0 + 0)}{(cm^{2} - 2cm + 1)^{2}})bc^{2}sqrt(e - se^{2})sqrt(e - 1) + \frac{bc^{2}(1 - s*2e)*\frac{1}{2}sqrt(e - 1)}{(cm^{2} - 2cm + 1)(e - se^{2})^{\frac{1}{2}}} + \frac{bc^{2}sqrt(e - se^{2})(1 + 0)*\frac{1}{2}}{(cm^{2} - 2cm + 1)(e - 1)^{\frac{1}{2}}} + (\frac{-(0 + 0 + 0)}{(cm^{2} - 2cm + 1)^{2}})bcsqrt(e - 1) + \frac{bc(1 + 0)*\frac{1}{2}}{(cm^{2} - 2cm + 1)(e - 1)^{\frac{1}{2}}}\\=& - \frac{bc^{2}msqrt(e + c)}{2(e - se^{2})^{\frac{1}{2}}} + \frac{bc^{2}msesqrt(e + c)}{(e - se^{2})^{\frac{1}{2}}} - \frac{bc^{2}msqrt(e - se^{2})}{2(e + c)^{\frac{1}{2}}} - \frac{bcm}{2(e + c)^{\frac{1}{2}}} + \frac{bc^{2}sqrt(e - 1)}{2(cm^{2} - 2cm + 1)(e - se^{2})^{\frac{1}{2}}} - \frac{bc^{2}sesqrt(e - 1)}{(cm^{2} - 2cm + 1)(e - se^{2})^{\frac{1}{2}}} + \frac{bc^{2}sqrt(e - se^{2})}{2(cm^{2} - 2cm + 1)(e - 1)^{\frac{1}{2}}} + \frac{bc}{2(cm^{2} - 2cm + 1)(e - 1)^{\frac{1}{2}}}\\ \end{split}\end{equation} \]

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